Asked by Anonymous

What is the first 12 term of an ap whose first term is 15 and the common difference is 13

Answers

Answered by Bosnian
In an Arithmetic progression:

a(n+1) = an + d

where

a1 = first term

d = the common difference

a1 = a1 = 15

a2 = a1 + d = 15 + 13 = 28

a3 = a2 + d = 28 + 13 = 41

a4 = a3 + d = 41 + 13 = 54

etc.



Answered by Bosnian
an = the nth term

a(n+1) = the n+1 th term

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