Asked by Divine

13x+22y=16
32x+12y=22
Answered by Anonymous
13x+22y=16....(i)
32x+12y=22....(ii)
eqn (ii) can be simplified by dividing through by 2, which gives 16x+6y=11
so we have;
13x+22y=16
16x+6y=11

by using elimination method, multiply eqn (i) by 3 and eqn (ii) by 11. So we have;
39x+66y=48
176x+66y=121

subtract eqn (i) from eqn (ii), ie,
(176x+66y=121)- (39x+66y=48)
so, we have;
137x=73 (divide both sides by 137)
x=73/137

substitute x=73/137 to the eqn 16x+6y=11

(16×73/137)+ 6y=11
1168/137+ 6y=11
6y=11-1168/137
6y=339/137 (divide both sides by 6)
y=339/822

therefore,
x=73/137 and y=339/822
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