Asked by Mukona
Five grams of a mixture of sand and table salt is analysed for the amount of NaCl (58.44).
The filtrate from the dissolution of the sample yields 0.8632 g of AgCl (143.32) after
precipitation with silver nitrate.
(a) Calculate the amount of NaCl in the sample in grams.
(b) Calculate the percentage of NaCl in the sample.
Answers
Answered by
DrBob222
g AgCl = 0.8632. Convert that to g NaCl.
0.8632 g AgCl x (molar mass NaCl/molar mass AgCl) = ? g NaCl
Then %NaCl = (grams NaCl/mass sample)*100 = ?
Post your work if you get stuck.
0.8632 g AgCl x (molar mass NaCl/molar mass AgCl) = ? g NaCl
Then %NaCl = (grams NaCl/mass sample)*100 = ?
Post your work if you get stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.