Question
Five grams of a mixture of sand and table salt is analysed for the amount of NaCl (58.44).
The filtrate from the dissolution of the sample yields 0.8632 g of AgCl (143.32) after
precipitation with silver nitrate.
(a) Calculate the amount of NaCl in the sample in grams.
(b) Calculate the percentage of NaCl in the sample.
Answers
DrBob222
g AgCl = 0.8632. Convert that to g NaCl.
0.8632 g AgCl x (molar mass NaCl/molar mass AgCl) = ? g NaCl
Then %NaCl = (grams NaCl/mass sample)*100 = ?
Post your work if you get stuck.
0.8632 g AgCl x (molar mass NaCl/molar mass AgCl) = ? g NaCl
Then %NaCl = (grams NaCl/mass sample)*100 = ?
Post your work if you get stuck.