Asked by khanyisile Maxhalanga
In the reaction: CH3I (aq) + NH2
-
(aq) → CH3NH2 (aq) + I- (aq), when the NH2
- concentration
alone was doubled, the rate doubled; when the CH3I concentration alone was increased by
1.5, the rate increased by 1.5 times. Write the rate law for the reaction
-
(aq) → CH3NH2 (aq) + I- (aq), when the NH2
- concentration
alone was doubled, the rate doubled; when the CH3I concentration alone was increased by
1.5, the rate increased by 1.5 times. Write the rate law for the reaction
Answers
Answered by
DrBob222
CH3I (aq) + NH2-(aq) → CH3NH2 (aq) + I- (aq)
rate = k(CH3I)(NH2-)
rate is 1st order in CH3I and 1st order in NH2^-
rate = k(CH3I)(NH2-)
rate is 1st order in CH3I and 1st order in NH2^-
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