Asked by Carl

Factor f(x)=40a^3-135b^3c^3
Answered by oobleck
40a^3-135b^3c^3
= 5(8a^3 - 27b^3c^3)
= 5((2a)^3 - (3bc)^3)
Now just apply your difference-of cubes-formula
Post your work if you get stuck
Answered by Carl
I got 5(2a-3bc)(4a^2+6abc+9bc)
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