Asked by a

A very large open tank is full of oil whose density is 800 kg/m3 . If the absolute pressure at the bottom of the tank is 1.81 x 10 5pa, then what is the depth of the oil? (Note that atmospheric pressure is 1.01 x 10 5pa)
Answered by a
q
Answered by Anonymous
Pa + rho g h = 1.01*10^5 + 800 kg/m^3 * 9.81 m/s^2 * h = 1.81*10^5
so
7848 h = 0.8^10^5 = 80000
h = 10.2 meters
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