Asked by Anonymous
J. S. Bach’s Prelude No. 2 in C Minor consists of 144 measures with each measure containing 12 notes. In a typical performance, 560 notes are played every minute. How many seconds does it take to perform the entire Prelude? Express your answer to the nearest second
Answers
Answered by
oobleck
144*12 = 1728 notes
1728 notes * 60sec/560notes = ____ seconds
1728 notes * 60sec/560notes = ____ seconds
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