Asked by heisenberg
The dinner options at Sue and Bill's wedding are fish, chicken, and steak. If 20% of the people order fish, 20% order chicken, and 180 people order steak, how many people are eating at the wedding?
A) 220
B) 252
C) 260
D) 300
Since we know that 20% of people ordered fish and another 20% ordered chicken, we can add that up to get a total population of these two food choices.
20% + 20% = 40%
Now that we have this percentage, we can find the total number of people eating at the wedding by seeing what 180 is 60% of.
180 * 100/60 = x
300 = x
Answer D: 300
A) 220
B) 252
C) 260
D) 300
Since we know that 20% of people ordered fish and another 20% ordered chicken, we can add that up to get a total population of these two food choices.
20% + 20% = 40%
Now that we have this percentage, we can find the total number of people eating at the wedding by seeing what 180 is 60% of.
180 * 100/60 = x
300 = x
Answer D: 300
Answers
Answered by
pepe
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