Asked by Kennedy
write equation that has base of 3 stretched vertically by factor of 2/3 reflected in y axis, asymptote of y=2 and passes through point (0,3,5)
Answers
Answered by
oobleck
the asymptote, stretch and reflection make me think
y = 2 + (2/3)*3^(-x)
To make that go through (0,3.5) we need to shift it right some
2 + (2/3) * 3^(h) = 3.5
h = 0.738
so we wind up with
y = 2 + (2/3) 3^(-(x-0.738)) = 2 + 3/2 * 3^-x
so, you sure that dilation was 2/3, and not 3/2 ??
y = 2 + (2/3)*3^(-x)
To make that go through (0,3.5) we need to shift it right some
2 + (2/3) * 3^(h) = 3.5
h = 0.738
so we wind up with
y = 2 + (2/3) 3^(-(x-0.738)) = 2 + 3/2 * 3^-x
so, you sure that dilation was 2/3, and not 3/2 ??
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