Asked by ade
x^2/3 -9x^1/3 +8
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Answered by
Anonymous
x^2/3 -9x^1/3 +8 = 0 maybe?
let y = x^1/3
y^2 -9 y + 8 = 0
(y-8) (y-1) = 0
y = 8 or y - 1
x^1/3 = 8 so x = 8^3
x^1/3 = 1 so x = 1
let y = x^1/3
y^2 -9 y + 8 = 0
(y-8) (y-1) = 0
y = 8 or y - 1
x^1/3 = 8 so x = 8^3
x^1/3 = 1 so x = 1
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