Asked by Lein
Calculate the mass of sodium oxide formed when 3.45 grams of sodium burns in air
Answers
Answered by
DrBob222
NOTE: The problem, as stated, is worked below; however, if the sodium is burned is excess oxygen the primary product formed is sodium peroxide, Na2O2.
4Na + O2 ==> 2Na2O
mols Na = grams/molar mass = 3.45/23 = 0.15
mols Na2O formed = 0.15 moles Na x (2 mols Na2O/4 mols Na) = 0.15 x (1/2) = ?
Then grams Na2O = mols Na2O x molar mass Na2O = ?
Post your work if you get stuck.
4Na + O2 ==> 2Na2O
mols Na = grams/molar mass = 3.45/23 = 0.15
mols Na2O formed = 0.15 moles Na x (2 mols Na2O/4 mols Na) = 0.15 x (1/2) = ?
Then grams Na2O = mols Na2O x molar mass Na2O = ?
Post your work if you get stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.