Asked by fai
p(5,4) and q(-1,2) are points on a straight line find the equation of the perpendicular bisector of pq given the answer in the form y=mx+c
Answers
Answered by
oobleck
the midpoint of PQ is (2,3)
The slope of PQ is 1/3
so your perpendicular bisector has point-slope equation
y-3 = -3(x-2)
now rearrange that as you will
The slope of PQ is 1/3
so your perpendicular bisector has point-slope equation
y-3 = -3(x-2)
now rearrange that as you will
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