Question
A 5kg mass on horizontal platform accelerated at the rate of 0.1m/s^2 when a horizontal force of 10newton is applied to it .Caculate the co-efficient between it and the platform(g=10m/s^2).
Answers
Anonymous
friction force = 5 * 10 * mu = 50 mu Newtons
net force = 10 - 50 mu Newtons
F = m a
10 -50 mu = 5 * 0.1 = 0.5
50 mu = 9.5
mu = 9.5 /50
net force = 10 - 50 mu Newtons
F = m a
10 -50 mu = 5 * 0.1 = 0.5
50 mu = 9.5
mu = 9.5 /50