Asked by MWAYI
a basket ball was thrown horizontally with an initial speed of 4.20m/s.A straight line drawn from the point of release to the point of landing makes an angle of 30.0° with the horizontal.From what height was the ball released?
Answers
Answered by
R_scott
let t equal time of flight
tan(30º) = 4.20 t / (1/2 * 9.8 * t^2)
solve for t
height = 1/2 * 9.8 * t^2
tan(30º) = 4.20 t / (1/2 * 9.8 * t^2)
solve for t
height = 1/2 * 9.8 * t^2
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