Asked by maladaptive
Determine the equation of the tangent line to the curve y = (2x^2 - 1) (2x^2 - 2x +1) when x = 2
Answers
Answered by
oobleck
y(2) = 35
y' = 2(8x^3 - 6x^2 + 1)
y'(2) = 82
so the line has equation
y-35 = 82(x-2)
y' = 2(8x^3 - 6x^2 + 1)
y'(2) = 82
so the line has equation
y-35 = 82(x-2)
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