Asked by Kaur
                Find value of 
(sin^2(2x)/cos^2(x)) + (sin^2(4x)/cos^2(2x)) + (sin^2(x)/cos^2(4x))
            
        (sin^2(2x)/cos^2(x)) + (sin^2(4x)/cos^2(2x)) + (sin^2(x)/cos^2(4x))
Answers
                    Answered by
            oobleck
            
    I sure don't see anything obvious, but
(2sinx cosx/cosx)^2 = 4sin^2x
(2sin(2x)cos(2x)/cos(2x))^2 = 4sin^2(2x) = 16sin^2x cos^2x
sin^2(x)/(cos^2(2x)-sin^2(2x))^2 = sin^2x/(sin^4x+cos^4x-6sin^2x cos^2x)
adding those up, you get
4sin^2x + 16sin^2x cos^2x + sin^2x/cos^2(4x)
= sin^2(x)/cos^2(4x) (4cos(2x)+12cos(4x)+4cos(6x)+1)
there are so many ways to massage this kind of stuff, you can stop almost anywhere and say that's it, unless you have some specific target in mind.
    
(2sinx cosx/cosx)^2 = 4sin^2x
(2sin(2x)cos(2x)/cos(2x))^2 = 4sin^2(2x) = 16sin^2x cos^2x
sin^2(x)/(cos^2(2x)-sin^2(2x))^2 = sin^2x/(sin^4x+cos^4x-6sin^2x cos^2x)
adding those up, you get
4sin^2x + 16sin^2x cos^2x + sin^2x/cos^2(4x)
= sin^2(x)/cos^2(4x) (4cos(2x)+12cos(4x)+4cos(6x)+1)
there are so many ways to massage this kind of stuff, you can stop almost anywhere and say that's it, unless you have some specific target in mind.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.