Asked by Brigid
Can someone please tell me if I've approached this homework problem correctly. A boy is running at his best speed of 6.0 m/s to catch a bus stopped at the lights. When he is 16 m from the bus, the light goes green and the bus pulls away at an acceleration of 1.0 m/s/s. Does he catch up with the bus and if yes how far does he have to run?
I set the distance of the boy equal to the distance of the bus in order for him to catch up to it and got: 6t=16 +1/2t^2, then solved the quad. equation to get t=4 or 8. So he ran 24m till he caught the bus. Did I do this correctly.
I set the distance of the boy equal to the distance of the bus in order for him to catch up to it and got: 6t=16 +1/2t^2, then solved the quad. equation to get t=4 or 8. So he ran 24m till he caught the bus. Did I do this correctly.
Answers
Answered by
drwls
That is the right equation. I will rewrite it as:
t^2 -12t + 32 = 0
(t-4)(t-8) = 0
(The t=8 time is when the bus would pull past him, if he didn't get on and passed it at t=4)
He will have run 24 s at t=4. Yes, you did it right. Nice job.
t^2 -12t + 32 = 0
(t-4)(t-8) = 0
(The t=8 time is when the bus would pull past him, if he didn't get on and passed it at t=4)
He will have run 24 s at t=4. Yes, you did it right. Nice job.
Answered by
Brigid
Yeah! thank you very much for checking my work. I can go to bed now.
Answered by
drwls
I meant 24 meters, not 24 seconds. You figured that out already
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.