Asked by jack

sherry invested a sum of money at 6% and invested a second sum that was $1,500 greater than the first sum, at 5%. if the total annual income was $570, how much was invested at each rate? Thank you for your assistance.
Answered by R_scott
.06 x + .05 (x + 1500) = 570

x is the 1st sum ... x + 1500 is the 2nd
Answered by jack
The answer is 4500 and 6000. I can't make this work. 6x+5(x+1500) 570
11x + 7500 = 5700 - 7500= 1800. 11x won't divide equally in to that. Any other suggestions? I tried to solve it initially by the same method you show, but couldn't get to work. What am I missing? Thanks again.
Answered by R_scott
.06 x + .05 x + 75 = 570 ... .11 x = 495 ... x = 4500

don't like decimals??

6x + 5(x + 1500) = 57000 ... eliminating decimals means adjusting factors

11x + 7500 = 57000 ... 11x = 49500 ... x = 4500
Answered by jack
yea! thank you.
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