Question
the length of a rectangle is 4 cm longer than it’s width. If the perimeter of the rectangle is 44 cm, find it’s area
Answers
Bosnian
L = length
W = width
P = perimeter
A = area
The length of a rectangle is 4 cm longer than it’s width mesns:
L = W + 4
P = 2 ( L + W ) = 44
Replacw L by W + 4 in this equation.
2 ( W + 4 + W ) = 44
2 ( 2 W + 4 ) = 44
Divide both sides by 2
2 W + 4 = 22
2 W = 22 - 4 = 18
W = 18 / 2
W = 9 cm
L = W + 4 = 9 + 4
L = 13 cm
A = L • W = 13 • 9
A = 117 cm²
W = width
P = perimeter
A = area
The length of a rectangle is 4 cm longer than it’s width mesns:
L = W + 4
P = 2 ( L + W ) = 44
Replacw L by W + 4 in this equation.
2 ( W + 4 + W ) = 44
2 ( 2 W + 4 ) = 44
Divide both sides by 2
2 W + 4 = 22
2 W = 22 - 4 = 18
W = 18 / 2
W = 9 cm
L = W + 4 = 9 + 4
L = 13 cm
A = L • W = 13 • 9
A = 117 cm²