Question
on earth an astronaut and his equipment weigh 5000 N while drifting weightless outside the international space station, the astronaut fires 110 N rocket backpack for 1.5 s. what is the resulting velocity relative to the space station?
Answers
astronaut mass (m) = weight / g = 5000 N / 9.8 m/s^2 ≈ 510 kg
acceleration = force / mass = 110 N / 510 kg ≈ 0.216 m/s^2
velocity = acceleration * time = 0.216 m/s^2 * 1.5 s = ?
acceleration = force / mass = 110 N / 510 kg ≈ 0.216 m/s^2
velocity = acceleration * time = 0.216 m/s^2 * 1.5 s = ?
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