Solve 2x + 3y = 1,3x^2 + 4xy - y^2 - 6=0 simultaneous equation using substitution method.

Answer 1

since y = (1-2x)/3, use that to find x:
3x^2 + 4x(1-2x)/3 - ((1-2x)/3)^2 - 6 = 0
expand and clear the fractions, and you are left with
x^2 - 16x + 55 = 0
(x-5)(x-11) = 0
x = 5 or 11
now you can find y