Question
What is the osmotic pressure created by 20.0 mg of insulin dissolved in 10.0 mL of solution at 27 degrees Celsius? The molar mass of insulin is 6020 g/mol.
a. 0.0818 torr
b. 6.22 torr
c. 3.11 torr
d. 0.0493 torr
a. 0.0818 torr
b. 6.22 torr
c. 3.11 torr
d. 0.0493 torr
Answers
pi = MRT
moles = g/molar mass = 0.02 g x (1 mol/6020 g) = ?
M = mols/L = moles from above/0.010 L = ?
You know R and T (remember T must be in K)
pi comes out in units of atm so multiply by 760 to convert to torr.
moles = g/molar mass = 0.02 g x (1 mol/6020 g) = ?
M = mols/L = moles from above/0.010 L = ?
You know R and T (remember T must be in K)
pi comes out in units of atm so multiply by 760 to convert to torr.
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