Asked by kelvin
What is the osmotic pressure created by 20.0 mg of insulin dissolved in 10.0 mL of solution at 27 degrees Celsius? The molar mass of insulin is 6020 g/mol.
a. 0.0818 torr
b. 6.22 torr
c. 3.11 torr
d. 0.0493 torr
a. 0.0818 torr
b. 6.22 torr
c. 3.11 torr
d. 0.0493 torr
Answers
Answered by
DrBob222
pi = MRT
moles = g/molar mass = 0.02 g x (1 mol/6020 g) = ?
M = mols/L = moles from above/0.010 L = ?
You know R and T (remember T must be in K)
pi comes out in units of atm so multiply by 760 to convert to torr.
moles = g/molar mass = 0.02 g x (1 mol/6020 g) = ?
M = mols/L = moles from above/0.010 L = ?
You know R and T (remember T must be in K)
pi comes out in units of atm so multiply by 760 to convert to torr.
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