Asked by MIN-WOO

A town p is 120km from town q on a bearing of north 60degree east town r is 76km from town p on bearing of south 50degree east. Find the bearing and distance of town q from r
Answered by MIN-WOO
RUBBISH
Answered by MIN-WOO
WRITE ALL THE ANSWER IN ENGLISH
Answered by Anonymous
angle QPR = 60 + 50 = 110 deg
law of cosines
120^2 + 76^2 = QR^2 - 2 *120 * 76 * cos 110

then
sin 110 / QR = sin PQR / 76
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