Asked by Bushra
I am an even number between 50 and 60 . The sum of my digits is 11 . Then who am I ?
Answers
Answered by
Bosnian
According to the question, the number lies between 50 and 60.
This means that the digit at the tens place must be 5, because for 60 sum of digits is 6 + 0 = 6
Also, according to the question, the digits sum up to give a total of 11.
a = tens place digit
b = one digit
tens place digit is 5
5 + b = 11
b = 11 - 5 = 6
Your number is 56
By the way even numbers 50 - 60 are:
50
Sum of digits = 5 + 0 = 5
52
Sum of digits = 5 + 2 = 7
54
Sum of digits = 5 + 4 = 9
56
Sum of digits = 5 + 6 = 11
58
Sum of digits = 5 + 8 = 13
60
Sum of digits = 6 + 0 = 6
Only the number 56 satisfies the condition that the sum of the digits is 11.
This means that the digit at the tens place must be 5, because for 60 sum of digits is 6 + 0 = 6
Also, according to the question, the digits sum up to give a total of 11.
a = tens place digit
b = one digit
tens place digit is 5
5 + b = 11
b = 11 - 5 = 6
Your number is 56
By the way even numbers 50 - 60 are:
50
Sum of digits = 5 + 0 = 5
52
Sum of digits = 5 + 2 = 7
54
Sum of digits = 5 + 4 = 9
56
Sum of digits = 5 + 6 = 11
58
Sum of digits = 5 + 8 = 13
60
Sum of digits = 6 + 0 = 6
Only the number 56 satisfies the condition that the sum of the digits is 11.
Answered by
Izrar
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