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Original Question
At what point on the curve x = 3t^2 + 2, y=t^3-8 does the tangent line have slope 1/2?Asked by rosie
At what point on the curve
x = 3t^2 + 6, y = t^3 − 3 does the tangent line have slope 1/2?
(x, y) =
x = 3t^2 + 6, y = t^3 − 3 does the tangent line have slope 1/2?
(x, y) =
Answers
Answered by
oobleck
well, at any point (x,y) the slope is
dy/dx = (dy/dt) / (dx/dt) = (3t^2)/(6t) = t/2
sure looks like t=1, so the point is (9,-2)
dy/dx = (dy/dt) / (dx/dt) = (3t^2)/(6t) = t/2
sure looks like t=1, so the point is (9,-2)
Answered by
rosie
thank you so much :) i wanted to make sure that my answer was right
Answered by
oobleck
should have posted <u>your</u> work so that we could check it ...
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