Asked by A man
A man is 4 times as old as his daughter,9 years ago the sum of their ages was 42 find their present ages .
Answers
Answered by
R_scott
m = 4 d
(m - 9) + (d - 9) = 42
substituting ... (4 d - 9) + (d - 9) = 42 ... 5 d - 18 = 42
solve for d , then substitute back to find m
(m - 9) + (d - 9) = 42
substituting ... (4 d - 9) + (d - 9) = 42 ... 5 d - 18 = 42
solve for d , then substitute back to find m
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