Question

so I'm very behind on math but there are questions that I need help with
q1- (2x)(10x)
a- 20x
b- 12x
c- 20x^2
d- and 5x
Q2= -3m(m+8)
a= -3m^2+24
b= -3m^2
c=-24m^2
c=-4m+5
Q3= 4d(2d-9)
a=8d-36d
b=-d
c=-28d^2
d=8d^2-36d
Q4= (3x+4)(x-2)
a=3x^2-2x-8
b=x-8
c=3x-2x-8
d=3x^2+2x+8
Q5= (2y-1)(x-2)
a=-2y+2
b=8y^2-10y-3
c=8y^2-10y+3
d= 8y^2-2y+3

Answer 1

#1. since multiplication is commutative,
(2x)(10x) = (2*10)(x*x) = 20x^2

#2. using the distributive property,
-3m(m+8) = (-3m)(m) + (-3m)(8) = -3m^2 - 24m
You appear to have a typo or two

#3. 4d(2d-9) = 4d*2d - 4d*9 = 8d^2 - 36d

#4. (3x+4)(x-2) = 3x(x-2) + 4(x-2)
= 3x^2 - 6x + 4x - 8
= 3x^2 - 2x - 8

#5. (2y-1)(x-2) = 2y(x-2) - 1(x-2)
= 2xy - 4y - x + 2
Looking at the choices, I suspect you meant
(2y-1)(y-2) = 2y(y-2) - 1(y-2)
= 2y^2 - 4y - y + 2
= 2y^2 - 5y + 2
Looks like you have mangled this one as well.