Asked by deshawn
The graph of y = StartRoot x EndRoot is transformed as shown in the graph below. Which equation represents the transformed function?
On a coordinate plane, a curve opens up and to the right. It starts at (0, 2) and then decreases through (4, 0) into quadrant 4.
y = negative StartRoot x EndRoot
y = StartRoot (negative x) EndRoot + 2
y = StartRoot (negative x) EndRoot minus 2
y = negative StartRoot x EndRoot minus 2
On a coordinate plane, a curve opens up and to the right. It starts at (0, 2) and then decreases through (4, 0) into quadrant 4.
y = negative StartRoot x EndRoot
y = StartRoot (negative x) EndRoot + 2
y = StartRoot (negative x) EndRoot minus 2
y = negative StartRoot x EndRoot minus 2
Answers
Answered by
oobleck
words, words, words !!
y = √x
you know that it is something like y = -√x
since its vertex is at (0,2) then it looks like
y = -√x + 2
check: -√4+2 = 0 ✅ so it goes through (4,0)
Looks like you have a typo somewhere
y = √x
you know that it is something like y = -√x
since its vertex is at (0,2) then it looks like
y = -√x + 2
check: -√4+2 = 0 ✅ so it goes through (4,0)
Looks like you have a typo somewhere
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