Asked by Anonymous
Imagine you have a 10 V power source and two resistors, one 20 Ohm and the other 5 Ohm. How would you arrange them to generate an average current of 2.5 A? How much current goes through each resistor?
Answers
Answered by
oobleck
There are only two ways to arrange the resistors:
series: R=20+5 = 25Ω, making a current of 10/25 = 0.4 A
parallel: 1/R + 1/5 + 1/20 = 1/4, so R = 4Ω, making a current of 10/4 = 2.5 A
So now you know that each resistor has a 10V drop across it, and you can easily figure the current in each.
series: R=20+5 = 25Ω, making a current of 10/25 = 0.4 A
parallel: 1/R + 1/5 + 1/20 = 1/4, so R = 4Ω, making a current of 10/4 = 2.5 A
So now you know that each resistor has a 10V drop across it, and you can easily figure the current in each.
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