Question
Calculate the number of electrons produced when 0.3375g of aluminum ionizes completely.
(Al=27,L=3.0×10^23)
(Al=27,L=3.0×10^23)
Answers
DrBob222
Al ==> Al^3+ + 3e
mols Al = g/atomic mass = 0.3375/27 = 0.0125
You get 3e x 0.125 = ? moles of electrons
There are 6.02E23 electrons in EACH mole of electrons.
Post your work if you get stuck.
mols Al = g/atomic mass = 0.3375/27 = 0.0125
You get 3e x 0.125 = ? moles of electrons
There are 6.02E23 electrons in EACH mole of electrons.
Post your work if you get stuck.
Berry Cerry
Can someone find the answers to Ecology Chemistry Unit Test
on pearson Please!? Please and thanks you soo much!!
on pearson Please!? Please and thanks you soo much!!