Asked by Favour
An elastic wire extends by 2.0cm when a load of 20newton hangs from it. what additional will be required to cause a further extension of 1cm?
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Answered by
Anonymous
F = k x
dF/dx = k
dF = k dx
k = 20 N/2cm = 10 N / cm
dF = 10 N/cm * 1cm = 10 Newtons
dF/dx = k
dF = k dx
k = 20 N/2cm = 10 N / cm
dF = 10 N/cm * 1cm = 10 Newtons
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