Question

H₂ (g) + CO₂ (g) ⇌ H₂O (g) + CO (g)

Initially, a sealed vessel contained only H₂ (g) with a partial pressure of 6 atm and CO₂ (g) with a partial pressure of 4 atm. The reaction above was allowed to come to equilibrium at a temperature of 700 K. At equilibrium, the partial pressure due to CO (g) was found to be 2 atm. What is the value of the equilibrium constant, Kp, for the reaction?

Answer 1

..................H₂ (g) + CO₂ (g) ⇌ H₂O (g) + CO (g)
I.................6 atm........4...............0...............0
C................-p..............-p.............+p............+p
E.................6-p...........4-p..............p..............p
The problem tells you that at equilibrium p = 2; therefore, at equilibrium (the E line), H2 is 6-2 = 4; 4-2 = 2. Substitute these values into Kp expression and solve for Kp.
Post your work if you get stuck.

Answer 2

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