Asked by Anonymous

Brandon has pennies, nickels, and dimes. He has a total of $10.20. There's are three times as many pennies as nickels. There are six times as many dimes as nickels. How many of each coin does he have?
Answered by oobleck
p+5n+10d = 1020
p = 3n
d = 6n
Now just solve as usual
Answered by Anonymous
3n + 5n + 10 (6n) = 1020
8n + 60n = 1020
68n = 1020
n = 15
p = 3n = 45
d = 6n = 80
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