The speed of a bullet of mass 10g is 720km\h.calculate the kinetic energy of the bullet in joules

Solve it for me

To calculate the kinetic energy of the bullet, we need to use the formula:

Kinetic Energy = (1/2) * mass * velocity^2

First, we need to convert the mass of the bullet from grams to kilograms:

1 gram = 0.001 kilograms

Therefore, mass = 10 grams * 0.001 kg/gram = 0.01 kg

Next, we need to convert the velocity of the bullet from km/h to m/s:

1 km = 1000 m
1 hour = 3600 seconds

Therefore, velocity = 720 km/h * (1000 m/1 km) * (1 h/3600 s) = 200 m/s

Now, we can substitute the values into the formula:

Kinetic Energy = (1/2) * 0.01 kg * (200 m/s)^2

Simplifying,

Kinetic Energy = 0.005 kg * (200 m/s)^2

Kinetic Energy = 0.005 kg * 40,000 m^2/s^2

Kinetic Energy = 200 joules

Therefore, the kinetic energy of the bullet is 200 joules.

To calculate the kinetic energy (KE) of the bullet, we can use the formula:

KE = (1/2) * mass * velocity^2

First, let's convert the mass of the bullet from grams to kilograms.
1 gram = 0.001 kilograms

So, the mass of the bullet is:
10 g = 10 * 0.001 kg = 0.01 kg

Next, let's convert the velocity of the bullet from km/h to m/s.
1 km/h = 0.2778 m/s

So, the velocity of the bullet is:
720 km/h = 720 * 0.2778 m/s = 200.16 m/s (approximately)

Now we can calculate the kinetic energy (KE) using the formula:

KE = (1/2) * mass * velocity^2
= (1/2) * 0.01 kg * (200.16 m/s)^2
= (1/2) * 0.01 kg * 40064.8064 m^2/s^2
= 0.005 * 40064.8064 J
= 200.324032 J

Therefore, the kinetic energy of the bullet is approximately 200.324032 joules.