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Joel reacted 0.9845 g of iron fillings with an excess of copper sulphate solution. When the reaction was complete the solution...Asked by Charlotte
                Joel reacted 0.9845 g of iron fillings with an excess of copper sulphate solution. When the reaction was complete the solution had changed from blue to green and a copper deposit weighing 1.024 g had formed in the solution. In this reaction, metallic iron is converted into ferrous ion (Fe2+) and cupric ion (Cu2+) is converted into metallic copper. 
Calculate the theoretical mass of copper that was expected to be produced and hence determine the percentage yield of Joel’s experiment.
            
            
        Calculate the theoretical mass of copper that was expected to be produced and hence determine the percentage yield of Joel’s experiment.
Answers
                    Answered by
            DrBob222
            
    See your other post for Fe moles used and Cu moles formed.
moles Fe used = theoretical moles Cu formed.
Theoretial moles Cu formed x atomic mass Cu = theoretical g Cu formed.
% yield = 100*(actual g Cu formed/theoretical g Cu formed)
Post your work if you get stuck.
    
moles Fe used = theoretical moles Cu formed.
Theoretial moles Cu formed x atomic mass Cu = theoretical g Cu formed.
% yield = 100*(actual g Cu formed/theoretical g Cu formed)
Post your work if you get stuck.
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