I need help with
write the equation of the line which contains the point (0,negavtive 3),
or written ars(0, -3)
and whose slope is 4.
if you want the equation in the form
y = mx + b
sub in -3 for y, 4 for m, and 0 for x
for
-3 = 4(0) + b
so b = -3
equation: y = 4x -3
We could have noticed that (0,-3) is the y-intercept and have directly into
y = 4x - 3
using the formula, y - (-3) = 4(x-0)
so y + 3 = 4x
y = 4x - 3