Asked by Anonymous
What is the temperature of 2.48 moles of gas stored in a 30.0 L container at 1559 mmHg
Answers
Answered by
DrBob222
PV = nRT
P = 1559 mm/760 = ? atm
V= 30.0 L
n = 2.48 moles
R = 0.08205 L*atm/mol*K
T = ? kelvin. If you want T in celsius then Kelvin = 273.15 + Celsius.
Post your work if you get stuck.
P = 1559 mm/760 = ? atm
V= 30.0 L
n = 2.48 moles
R = 0.08205 L*atm/mol*K
T = ? kelvin. If you want T in celsius then Kelvin = 273.15 + Celsius.
Post your work if you get stuck.
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