what volume of 0.175 M NaP04 solution is required to react with 71.55 ml of 0.102 m CuCl2

1 answer

Your question is confusing for more than one reason.
1. First sodium phosphate is Na3PO4.
2. Second you use 0.102 m CuCl2. m stands for molality. I'm sure you meant M. That means molarity.
3. You ask what volume is required to react with .... Actually, ANY volume will react with it. I expect you mean what volume Na3PO4 is required to react completely with CuCl2. That's what I will assume. The balanced equation is as follows:
2Na3PO4 + 3CuCl2 ==> Cu3(PO4)2(s) + 6NaCl
How many moles of CuCl2 do you have? That's M x L = 0.102 M x 0.07155 = 0.007298
How many moles of Na3PO4 will be needed? That's
0.007298 mols CuCl2 x (2 moles Na3PO4/3 moles CuCl2) =
0.007298 x 2/3 = 0.004865 moles Na3PO4.
Convert that to volume: moles = M x L. Substitute M from the problem, mols Na3PO4 from the calculation above and solve for L. Post your work if you get stuck.