Asked by Anonymous
There are some stickers in albums A and B. 50% of the stickers in album A and 20% of the stickers in album B are round stickers. There is an equal number of square stickers in both albums. If there are 51 more round stickers in album A than in album B, how many stickers are there in both albums altogether?
Answers
Answered by
Anonymous
50% of round stickers x
50% of square stickers x
(albums A)
20% of round stickers x/4
80% of square stickers x
(albums B)
Let x = # of square stickers in albums A
So # of round stickers in albums A = x
# of square stickers in albums B = x
# of round stickers in albums B = x/4
Then, x - x/4 = 51
3/4x = 51
x = 51 * 4/3 = 68
The stickers in both albums altogether:
x + x + x/4 + x = 3.25 * 68 = 221
50% of square stickers x
(albums A)
20% of round stickers x/4
80% of square stickers x
(albums B)
Let x = # of square stickers in albums A
So # of round stickers in albums A = x
# of square stickers in albums B = x
# of round stickers in albums B = x/4
Then, x - x/4 = 51
3/4x = 51
x = 51 * 4/3 = 68
The stickers in both albums altogether:
x + x + x/4 + x = 3.25 * 68 = 221
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