Question
In the balanced reaction shown below, what is the ratio of lead nitrate (Pb(NO3)2) to potassium iodide (KI)?
Pb(NO3)2 + 2KI --> PbI2 + 2KNO3
B. 3:2
C. 3:1 <-----my answer
D. 1:2
Pb(NO3)2 + 2KI --> PbI2 + 2KNO3
B. 3:2
C. 3:1 <-----my answer
D. 1:2
Answers
I would write 1:2 since 1 mol Pb(NO3)2 = 2 moles KI.
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