Asked by Anonymous
                The Keq of a reaction is 4 x 10-7. At equilibrium:
a. the reactants are favored.
b. the products are favored.
c. the reactants and products are present in equal amounts.
d. the rate of the reverse reaction is much greater than the rate of the
forward reaction.
            
        a. the reactants are favored.
b. the products are favored.
c. the reactants and products are present in equal amounts.
d. the rate of the reverse reaction is much greater than the rate of the
forward reaction.
Answers
                    Answered by
            DrBob222
            
    Think this through.
Keq = 4.5E-7 = (products)/(reactants)
At equilibrium you know forward rate = reverse rate so d can't be right.
If c is right then products = reactants so K = 1; that is not so and c can't be right.
That leaves either a or b for the answer. For Keq to be such a SMALL number that makes the (products) small and (reactants) large. So the answer is ..........?
    
Keq = 4.5E-7 = (products)/(reactants)
At equilibrium you know forward rate = reverse rate so d can't be right.
If c is right then products = reactants so K = 1; that is not so and c can't be right.
That leaves either a or b for the answer. For Keq to be such a SMALL number that makes the (products) small and (reactants) large. So the answer is ..........?
                    Answered by
            nmf
            
    The Keq of a reaction is 4 x 10-7. At equilibrium:
    
                    Answered by
            nmf
            
    a. the reactants are favored.
    
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