Asked by vee
The data shows the total number of employee medical leave days taken for on-the-job accidents in the
first six months of the year: 12, 6, 15, 9, 18, 12. Use the data for the Exercise.
Find the standard deviation.
first six months of the year: 12, 6, 15, 9, 18, 12. Use the data for the Exercise.
Find the standard deviation.
Answers
Answered by
oobleck
mean µ = 12
|deviations|: 0,6,3,3,6,0
squares: 0,36,9,9,36,0
sum of squares: 90
sample variance: 90/5 = 18
sample std σ = √18 = 4.243
|deviations|: 0,6,3,3,6,0
squares: 0,36,9,9,36,0
sum of squares: 90
sample variance: 90/5 = 18
sample std σ = √18 = 4.243
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