Asked by Connexus_Girl

How much would a 10th dog have to weigh for the average weight in part (a) to be 250 pounds? Explain how you determined your answer.

70, 51, 65,65, 40, 7,70,22, 45
The average is: 54.375
I don't want the answer i just want a hint or something or just the steps to find it.
Also i neeed this answer RN. also thank u

Answered by oobleck
250 lbs? with all those small dogs?
oh, well.
x + (sum of all the 9 weights) = 10*250
or
(x + 9*54.375)/10 = 250

It better be a horse!
Answered by Connexus_Girl
Fr. thats what I said, It's a stupid question, for when talking abt dogs. lol, but anyways thanks for getting me a hint.
Answered by Connexus_Girl
Can SOMEONE PLZ HELP ME!!! I need more guidance... Like i know that this is a stupid question but come on guys, plz help me
Answered by Connexus_Girl
*Stupid question*
Answered by Connexus_Girl
*stpid
Answered by Connexus_Girl
Plz Help ME, Im desperate at this point tbh, and stressing hard abt this stpid portfolio, so can yall just help me.
Answered by oobleck
what more do you want? I gave you two equivalent formulas to find x, the required weight.

you want the total weight of the 10 dogs to be 10 times the desired average.
Answered by Connexus_Girl
ok jeez im sorry, i actually got the answerso thank u. btw also im sorry if i sounded desperate, or being hard to help, i was just stressed. But really thank u ooblek
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