Question
A. If the parabola opens up, down, left, or right.
B. The vertex of the parabola.
C. The location of the focus.
D. The equation of the directrix.
E. The equation of the axis of symmetry.
1. x - 5 = -1/40(y - 5)2
B. The vertex of the parabola.
C. The location of the focus.
D. The equation of the directrix.
E. The equation of the axis of symmetry.
1. x - 5 = -1/40(y - 5)2
Answers
Anonymous
Perhaps you mean
x - 5 = -(1/40) (y - 5)^2
(y - 5)^2= -40 (x-5)= 4 (-10) (x-5)
-10 is negative so opens left
vertex at (5,5)
vertex to focus= -10
vertex to directrix = +10
LR = 4*10 = 40
y = 5 is line of symmetry [ (y-5)^2 same above and below]
x - 5 = -(1/40) (y - 5)^2
(y - 5)^2= -40 (x-5)= 4 (-10) (x-5)
-10 is negative so opens left
vertex at (5,5)
vertex to focus= -10
vertex to directrix = +10
LR = 4*10 = 40
y = 5 is line of symmetry [ (y-5)^2 same above and below]