Question

In AFGH, FH = 9 ft, FG = 11 ft, and m <F = 65°. Find m <G. Round your answer to the nearest tenth.
a) 41.4
b) 10.9
c) 48.6
d) 89.7



plz help
since a quadrilateral AFGH cannot be determined from what you have said, I assume that you meant ∆FGH. In that case,
GH^2 = 11^2 + 9^2 - 2(11)(9) cos65°
sinG/9 = sin65°/GH
Now just crank it out

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