Asked by tt
if the nth term is n(n+1) then what term is 182?
Answers
Answered by
oobleck
just solve
n(n+1) = 182
n^2 + n - 182 = 0
so which two factors of 182 differ by 1?
√182 = 13.5
so it looks like you have
(n-13)(n+14) = 0
n(n+1) = 182
n^2 + n - 182 = 0
so which two factors of 182 differ by 1?
√182 = 13.5
so it looks like you have
(n-13)(n+14) = 0
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