Asked by Mac
Determine the solution set to the equation: 2sin^2x+cosx-2=0
Answers
Answered by
Reiny
I will assume your domain is 0 --- 360
2sin^2x+cosx-2=0
2(1- cos^2x) + cosx - 2 = 0
2 - 2cos^2x + cosx - 2 = 0
2cos^2x - cosx = 0
cosx(2cosx - 1) = 0
cosx = 0 or cosx = 1/2
x = 90º or 270º or x = 60º or x = 300º
these can be easily converted to radians
2sin^2x+cosx-2=0
2(1- cos^2x) + cosx - 2 = 0
2 - 2cos^2x + cosx - 2 = 0
2cos^2x - cosx = 0
cosx(2cosx - 1) = 0
cosx = 0 or cosx = 1/2
x = 90º or 270º or x = 60º or x = 300º
these can be easily converted to radians
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