Asked by Liz
write a quadratic equation for which the graphs of the equation opens downward, the vertex is (0,3). the domain includes all real numbers, and the range is y<-3.
Answers
Answered by
oobleck
the vertex is (0,3) so the equation is
y = ax^2 + 3
since it opens downward,any negative value for a will work.
Unfortunately, this has a range of y ≤ 3, not y < -3.
If the vertex is at (0,3), clearly the range includes 3.
y = ax^2 + 3
since it opens downward,any negative value for a will work.
Unfortunately, this has a range of y ≤ 3, not y < -3.
If the vertex is at (0,3), clearly the range includes 3.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.