Asked by Anonymous
How would you balance this equation to find the coefficients of each compound and the spectator ion ?
KI(aq)+ KMnO4 (aq) + H2O= I2(s) + MnO2(s) + KOH(aq)
KI(aq)+ KMnO4 (aq) + H2O= I2(s) + MnO2(s) + KOH(aq)
Answers
Answered by
oobleck
6KI + 2KMnO4 + 4H2O → 3I2 + 2MnO2 + 8KOH
Answered by
DrBob222
6KI + 2KMnO4 + 4H2O → 3I2 + 2MnO2 + 8KOH
To find the spectator ions, first divide the individual reactants/products into their respetive ions.
6K^+ + 6I^- + 2K^+ + 2MnO4^- + 4H2O → 3I2 + 2MnO2 + 8K^+ + 8OH^-
Then note the ions present at the end. The ions that apear on both sides of the equation are the spectator ions. K^+ ions are the spectator ions.
To find the spectator ions, first divide the individual reactants/products into their respetive ions.
6K^+ + 6I^- + 2K^+ + 2MnO4^- + 4H2O → 3I2 + 2MnO2 + 8K^+ + 8OH^-
Then note the ions present at the end. The ions that apear on both sides of the equation are the spectator ions. K^+ ions are the spectator ions.
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