Asked by lizzy

Find (f −1)'(a). f(x) = 3x^3 + 2 sin x + 3 cos x, a = 3

I don't know how to solve this question

Answered by oobleck
f'(x) = 9x^2 + 2cosx
f(0) = 3
so (f<sup><sup>-1</sup></sup>)'(3) = 1/f'(0) = 1/2
Answered by lizzy
ah ty!
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